Question

Solve for ' x ' = √a/b=[b/a]^-3x​

Answer 1

Answer:

$\huge{\mathbb{ANSWER : -}}$

given root under a/b =(b/a)^1-3x

As (a/b)^1/2=(b/a)^1-3x

Then (b/a)^-1/2 =(b/a)^1-3x

Then solve for x in

-1/2=1-3x

You get x =1/2

Answer 2

Answer:

Here, (a/b)^1/2=(b/a)^(1-3x)

=> (b/a)^-1/2=(b/a)^(1-3x)

=> 1-3x = -1/2

=> 3x = 1+1/2

=> 3x = 3/2

=> x =3/2×1/3

=> x = 1/2

hence, x = 1/2 answer.