Question

Solve for x:
A) $\orange{|x + 1| + |x| > 3}$
B) $\orange{ | \dfrac{2}{x - 4} | > 1}... \bold{x \neq3}$
Find the value of:
$\sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6 + ...} } } }$
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Answer 1

Step-by-step explanation:

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