Question

solve for x,a²b²x²+b²x-a²x-1=0​

Answer 1

Answer:

solved

Step-by-step explanation:

a²b²x²+b²x-a²x-1=0​

a²b²x²+(b² - a² )x - 1 = 0​

x = (a²-b²) ± √{(a²-b²)²+ 4a²b²} ÷ 2

x = (a²-b²) ± √{(a²+ b²)²} ÷ 2

x = { (a²-b²) ±   (a²+ b²)} ÷ 2

x = a² , - b²