solve for x:
a2b2x2+b2x -a2x - 1 =0
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Answered by
309
a²b²x²+b²x-a²x-1 =0
b²x(a²x+1)-1(a²x+1)=0
(b²x-1)(a²x+1)=0
if b²x-1=0
b²x=1
x=1/b²
if a²x+1=0
a²x=-1
x=-1/a²
PLEASE SELECT MY ANSWERS AS BRAINLIEST
b²x(a²x+1)-1(a²x+1)=0
(b²x-1)(a²x+1)=0
if b²x-1=0
b²x=1
x=1/b²
if a²x+1=0
a²x=-1
x=-1/a²
PLEASE SELECT MY ANSWERS AS BRAINLIEST
Answered by
105
Solution is in the given attachment.
Regrets for handwriting _/\_
_______________________
Let's see some related terms ;
Factorisation : It is the term that means to differ the factors of a given expression.
Linear equations in two variables :
▪️A linear equation in two variables has infinitely many solutions.
▪️Standard form of a linear equation in two variables is « ax + by + c = 0 », where a and b are coefficients of x and y respectively and she is a constant.
_______________________
Thanks for the question!
Regrets for handwriting _/\_
_______________________
Let's see some related terms ;
Factorisation : It is the term that means to differ the factors of a given expression.
Linear equations in two variables :
▪️A linear equation in two variables has infinitely many solutions.
▪️Standard form of a linear equation in two variables is « ax + by + c = 0 », where a and b are coefficients of x and y respectively and she is a constant.
_______________________
Thanks for the question!
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