Math, asked by Lazyplayer12, 1 year ago

Solve for X
All of them...
Please send ans in pic not in text format....

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Answers

Answered by adityashreebhap6o3f2
0

Answer:

1st - 2√6/6 and 2√6/6

2nd - +- √7/4

Answered by Anonymous
1

1

3 {x}^{2}  + 2 \sqrt{6} x +2 = 0 \\  {( \sqrt{3} x +  \sqrt{2} })^{2}  = 0 \\ x =   - \frac{ \sqrt{2} }{ \sqrt{3} }

2.

2 {x}^{2}  - x +  \frac{1}{8} = 0 \\  4 {x}^{2}  - 2x +  \frac{1}{4}  = 0 \\  {(2x +  \frac{1}{2} })^{2}  = 0 \\ x =  -  \frac{1}{4}

3

 \frac{x}{7}  -  \frac{1}{x - 2}  = 3 \\  {x}^{2}  - 9x  = 21x - 42 \\  {x}^{2}  - 30x + 42 = 0 \\  {x}^{2}  - 30x + 225 - 182 = 0 \\  {(x - 15)}^{2}  - 182 = 0 \\ (x - 15 +  \sqrt{182} )(x - 15 -  \sqrt{182} ) = 0 \\ x = 15 -  \sqrt{182}  \\ and \\ x = 15 +  \sqrt{182}

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