Math, asked by guruyadawad60, 1 year ago

solve for x&y 2x+4y=4 & 3x-y = 2

Answers

Answered by rkd55
5
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2x+4y = 4 ........... Equation (1) ×3

3x-y = 2 .............. Equation (2) ×2
_______________ (By multiplying value of 'x')
6x+12y = 12

6x-2y = 4
(-) (+) = (-)
_______________ ( By substraction )
0 + 14y = 12

14y = 12

y = 12/14

y = 6/7


Now, putting the value of "y" in equation (1).....

2x+4y = 4

2x+ 4×6/7 = 4

2x+24/7 = 4

14x+24
----------- = 4
7

14x+24 = 28

14x = 28-24

14x = 4

x = 4/14

x = 2/7



So, X = 2/7
> Answer..
Y = 6/7

Hope this will help you

Answered by Anonymous
33
\textbf{Question - }

solve for x&y 2x+4y=4 & 3x-y = 2

\textbf{Solution - }

2x + 4y = 4 - - - - (1) \\ 3x - y = 2 - - - -(2)

\textsf{from \: elimination \: method \: - }

Add eq(1) and eq(2)×4

 \: \: 2x + 4y = 4 \\ 12x - 4y = 8 \\
____________
14x = 12 \\ x = \frac{12}{14} \\ x = \frac{6}{7}

Putting the value of x in eq (2)

3x - y = 2 \\ 3 \times \frac{6}{7} - y = 2 \\ \frac{18}{7} - y = 2 \\ y = \frac{18}{7} - 2 \\ y = \frac{18 - 14}{7} \\ y = \frac{4}{7}

__________________________

\huge\bold{Thanks}

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