Question

Solve for x&y
3/x - 1/y = -9
2/x+3/y=5​

Answer 1

$\huge{\mathfrak{\red{Answer}}}$

$\frac{3}{x} - \frac{1}{y} = - 9..........(1) \\ \frac{2}{x} + \frac{3}{y} = \: \: 5...........(2) \\ multiply \: by \: xy \\ (1) \times - 3=> 3x - 9y = 27 \\ (2) = > 3x + 2y = 5 \\ - - - - - - - - - - - - \\ - 11y = 22 \\ y = - 2 ........(3)\\ sub \: (3) in (3x + 2y = 5) \\ 3x - 4 = 5 \\ 3x = 9 \\ x = 3$

☜☆☞ I hope it is the answer Pls make me as brainliest pls ☜☆☞

Answer 2

Answer

The required values are :

x = 1/-2

y = 1/3

Given

• $\sf \frac{3}{x} - \frac{1}{y} = - 9$
• $\sf \frac{2}{x} + \frac{3}{y} = 5$

To Find

• The value of x and y

Solution

Let us consider 1/x = p and 1/y = q so that the above equations becomes :

$\sf3p - q = - 9 \\ \implies \sf9p - 3q = - 27.........(1)$

and the other one

$\sf2p + 3q = 5...........(2)$

Adding the equations (1) and (2)

$\sf \implies9p - 3q + 2p + 3q = - 27 + 5 \\ \sf\implies11p = - 22 \\ \sf \implies p = - 2$

Putting the value of p in equation (2)

$\sf \implies2( - 2) + 3q = 5 \\ \sf \implies - 4 + 3q = 5 \\ \sf\implies3q = 9 \\ \sf \implies q = 3$

Since we had assumed p = 1/x and q = 1/y so

$\sf \frac{1}{x} = - 2 \: \: and \: \: \: \frac{1}{y} = 3 \\ \sf \implies \boxed{x = \frac{1}{ - 2} } \: \: and \implies \boxed{y = \frac{1}{3} }$