Question

Solve for x&y : 7/3^x - 6/2^y = 15 & 8/3^x = 9/2^y

Answer 1

The required answer is in the attachment.

Answer 2

HELLO DEAR,


given that:-


let

1/3^x=p------------(1)

and

1/2^y=q --------------(2)


use this value in the Equation

we get new Equation

7p -6q=15--------------(3)

and
8p -9q=0---------------(4)


from (3)and(4) -
multiply by 3 in (3)
and by 3 in(4)

21p -18q=45
16p- 18q=0
- +
___________
5p=45
p=9

Put in (3)

We get,

7×9 -6q=15

6q=63-15

q=48/6

q=8 and p=9

Now,

From (1)

P=9=1/3^x

9×3^x=1

3^(x+2)=3^0

X+2=0

X= -2


And,
from (2)

q=8=1/2^y

2³×2^y=1

2^(3+Y)=2^0

3+Y=0

Y= (-3) AND X= (- 2)



I HOPE ITS HELP YOU DEAR,
THANKS