Solve for x&y : 7/3^x - 6/2^y = 15 & 8/3^x = 9/2^y
Answers
Answered by
7
The required answer is in the attachment.
Attachments:
rohitkumargupta:
and value of y
Answered by
16
HELLO DEAR,
given that:-
let
1/3^x=p------------(1)
and
1/2^y=q --------------(2)
use this value in the Equation
we get new Equation
7p -6q=15--------------(3)
and
8p -9q=0---------------(4)
from (3)and(4) -
multiply by 3 in (3)
and by 3 in(4)
21p -18q=45
16p- 18q=0
- +
___________
5p=45
p=9
Put in (3)
We get,
7×9 -6q=15
6q=63-15
q=48/6
q=8 and p=9
Now,
From (1)
P=9=1/3^x
9×3^x=1
3^(x+2)=3^0
X+2=0
X= -2
And,
from (2)
q=8=1/2^y
2³×2^y=1
2^(3+Y)=2^0
3+Y=0
Y= (-3) AND X= (- 2)
I HOPE ITS HELP YOU DEAR,
THANKS
given that:-
let
1/3^x=p------------(1)
and
1/2^y=q --------------(2)
use this value in the Equation
we get new Equation
7p -6q=15--------------(3)
and
8p -9q=0---------------(4)
from (3)and(4) -
multiply by 3 in (3)
and by 3 in(4)
21p -18q=45
16p- 18q=0
- +
___________
5p=45
p=9
Put in (3)
We get,
7×9 -6q=15
6q=63-15
q=48/6
q=8 and p=9
Now,
From (1)
P=9=1/3^x
9×3^x=1
3^(x+2)=3^0
X+2=0
X= -2
And,
from (2)
q=8=1/2^y
2³×2^y=1
2^(3+Y)=2^0
3+Y=0
Y= (-3) AND X= (- 2)
I HOPE ITS HELP YOU DEAR,
THANKS
Similar questions