solve for x&y in 3x+2y+2=0 & 5x+3y=22
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Step-by-step explanation:
3x+2y+2=0 as equation1
5x+3y-22=0 as equation 2
multiply 1 equation by 3
9x+6y+6=0
multiply 2 equation by 2
10x+6y-44=0
subtract 1 equation from 2 one
10x+6y-44-9x-6y-6=0
x-50=0
x=50
put value of x in 1 equation
150+2y+2=0
152+2y=0
2y=-152
y=-76
Answered by
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Step-by-step explanation:
3x+2y+2=0
5x+3y=22
3x+2y=-2--------(3)
5x+3y=22-------(4)
multiply equation (3)by5 and(4) by 3 we get
15x+10y=-10--------(5)
15x+9y =66 --------(6)
now,subtract equation (6) from (5) we get
y=-76 substitute the value of y in equation (5)we get
15x+10y=-10
15x+10(-76)=-10
15x-760=-10
15x=-10+760
15x=750
x=750/15
x=50
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