solve for X & Y
x/2+y/3=2, x+2y=8
Answers
Answered by
17
Given :-
x/2 + y/3 = 2 .........eq( 1 )
x + 2y = 8 ................eq( 2 )
Solution :-
Take equation 1
x/ 2 + y/3 = 2
Solve by taking LCM
3x + 2y / 6 = 2
3x + 2y = 2*6
3x = 12 - 2y
x = (12 - 2y)/3 ...........eq( 3 )
Take eq( 2)
x + 2y = 8
Subsitute eq (3) in eq( 2)
(12 - 2y)/3 + 2y = 8
By taking LCM
12 - 2y + 6y /3 = 8
12 - 2y + 6y = 8 * 3
12 + 4y = 24
4y = 24 - 12
4y = 12
y = 12/4
y = 3 ...........eq( 4)
Subsitute eq(4) in eq( 1)
x/2 + y/3 = 2
Put the required value of y in the equation 4
x/ 2 + 3/3 = 2
x/2 + 1 = 2
By taking LCM
x + 2 / 2 = 2
x + 2 = 2*2
x + 2 = 4
x = 4 - 2
x = 2
Hence, The value of x is 2
The value of y is 3
Verification :-
2/2 + 3/3 = 2
1 + 1 = 2
2 = 2
LHS = RHS
2 + 2 * 3 = 8
2 + 6 = 8
8 = 8
LHS = RHS
Answered by
10
Տ0Ꮮղ:-
───
Х/2 + Ꮍ/3 = 2 ─────❶
Х+ 2Ꮍ =8 ───────➋
ꜰʀᴏᴍ ᴇQ ❶
X/2+ Ꮍ/3 =2
=> Х/2 = 2- Ꮍ/2
=> Х/2 = 4-Ꮍ/2
=> 2Х = 8-Ꮍ
=> Х = 8-Ꮍ/2
=> Х = 4-Ꮍ
ᴘᴜᴛɪɴɢ ᴠᴀʟᴜᴇ ᴏꜰ "x" ꜰʀᴏᴍ ᴇQ ❷
x+ 2Ꮍ = 8
=> 4-Ꮍ + 2Ꮍ = 8
=> Ꮍ = 8-4
=> Ꮍ = 4
ᴘᴜᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏꜰ "ʏ" ꜰʀᴏᴍ Х= 2-Ꮍ
Х= 2-4
=>Х = 2-4
=> Х = 2
ᴡᴇ ꜰɪɴᴅ,
Х= 2
Ꮍ= 4
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