Question

solve for x and y,0.04x+0.02y=5;0.5(x-2)-0.4y=29

Answer 1

Answer:

Step-by-step explanation:

100(0.04x+0.02y)=100*5---(1)

10[0.5(x-2)-0.4y]=10*29---(2)

(1)== 4x+2y=500--(3)

(2)== 5x-4y=300--(4)

Solve Both 3 and 4 equations

We get x=100

Y=50

Answer 2

hope this helps anyone who is trying to find an answer