solve for x and y,0.04x+0.02y=5;0.5(x-2)-0.4y=29
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Answer:
Step-by-step explanation:
100(0.04x+0.02y)=100*5---(1)
10[0.5(x-2)-0.4y]=10*29---(2)
(1)== 4x+2y=500--(3)
(2)== 5x-4y=300--(4)
Solve Both 3 and 4 equations
We get x=100
Y=50
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hope this helps anyone who is trying to find an answer
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