Solve for x and y
1/3x + y + 1/3x - y = 3/4
1/2(3x + y ) - 1/2(3x _ y ) = - 1/8
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1/3x+y+1/3x-y=3/4
2/3x=3/4
x=3/4×3/2
x=9/8
1/2(3x+y)-1/2(3x-y)= -1/8
take {1/2} in common
1/2[(3x+y)-(3x-y)]=-1/8
1/2[3x+y-3x+y)]= -1/8
1/2(2y)= -1/8
y= -1/8
2/3x=3/4
x=3/4×3/2
x=9/8
1/2(3x+y)-1/2(3x-y)= -1/8
take {1/2} in common
1/2[(3x+y)-(3x-y)]=-1/8
1/2[3x+y-3x+y)]= -1/8
1/2(2y)= -1/8
y= -1/8
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