solve for x and y 12x+y-8=0 2x+3y+10=0
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Answered by
1
Heya !!!
12X + Y - 8 = 0
12X + Y = 8 ---------(1)
And,
2X + 3Y + 10 = 0
2X + 3Y = -10 -------(2)
From equation (1) we get,
12X + Y = 8
12X = ( 8 - Y )
X = ( 8 - Y )/12 -------(3)
Putting the value of X in equation (2)
2X + 3Y = -10
2 × ( 8 - Y /12) + 3Y = -10
8 - Y/6 + 3Y = -10
8 - Y + 18Y = -60
17Y = -60-8
Y = -68/17 = -4
Putting the value of Y in equation (3)
X = ( 8 - Y)/12 = (8+4)/12 = 12/12
X = 1.
Hence,
X = 1 and Y = -4.
★ HOPE IT WILL HELP YOU ★
12X + Y - 8 = 0
12X + Y = 8 ---------(1)
And,
2X + 3Y + 10 = 0
2X + 3Y = -10 -------(2)
From equation (1) we get,
12X + Y = 8
12X = ( 8 - Y )
X = ( 8 - Y )/12 -------(3)
Putting the value of X in equation (2)
2X + 3Y = -10
2 × ( 8 - Y /12) + 3Y = -10
8 - Y/6 + 3Y = -10
8 - Y + 18Y = -60
17Y = -60-8
Y = -68/17 = -4
Putting the value of Y in equation (3)
X = ( 8 - Y)/12 = (8+4)/12 = 12/12
X = 1.
Hence,
X = 1 and Y = -4.
★ HOPE IT WILL HELP YOU ★
Answered by
1
take first 2x+3y+10=0
and get seperate the x you get a value of x put in 12x+y-8=0 and you get y value and put y value in the 2 equation u get x = 1
k bhai
and get seperate the x you get a value of x put in 12x+y-8=0 and you get y value and put y value in the 2 equation u get x = 1
k bhai
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