solve for X and Y 2 by X + 2 by 3 Y is equal to 1 by 6
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Answered by
1
LET 2^x=3^y=(1/6)^z=k
Therefore,
K^(1/x)=2
K^(1/y)=3
K^(1/z)=(1/6)
Multiply these 3 equations to get:
K^[(1/x)+(1/y)+(1/z)]=1
Hope it's help you
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Therefore,
K^(1/x)=2
K^(1/y)=3
K^(1/z)=(1/6)
Multiply these 3 equations to get:
K^[(1/x)+(1/y)+(1/z)]=1
Hope it's help you
Please mark me in brain list answer
Answered by
0
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