Math, asked by alriacarolyndsouza, 6 months ago

solve for x and y .2/x-1+3/y-2=1 and 5/x-1+6/y-2=7​

Answers

Answered by ItzRadhika
16

\bf\underline{\underline{\green{SOLUTION:-}}}

Given

  • 2/x-1 + 3/y-2 =1
  • 5/x-1 + 6/y-2 =7

To Calculate

  • Value of x and y

Step by step explanation

  • 2/x-1 + 3/y-2 =1____________(1)
  • 5/x-1 + 6/y-2 =7____________(2)

 =  \:  \frac{2}{x - 1}  +  \frac{3}{y - 2}  = 1

Let 1/x-1 = u And 1/y-2 = v

2u +3v=1____________(3)

 = \:  \frac{5}{x - 1}  +  \frac{6}{y - 2}  = 7

= 5u+6v=7_________(4)

On Multiply eq3 by 2

2(2u+3v=1)

⟹ 4u+6v=2_____________(5)

On subtracting eq5 from 4

5u+6v=7

4u+6v=2

__________

v= 5

__________

Putting value of v in eq 5

4u+6v=2

⟹4u+6×5=2

⟹4u+30=2

⟹ 4u = 2-30

⟹ 4u = -28

⟹ u= -28/4

⟹ u= -7

1/x-1 = u

⟹ \:  \frac{1}{x - 1}  = - 7

 =  \frac{1}{x - 1}  =  \frac{ - 7}{1}  \\  \\  = 7(x - 1) = 1 \\  \\  = 7x - 7 = 1 \\  \\  = 7x = 1 + 7 \\  \\  = 7x = 8 \\  \\  = x =  \frac{8}{7}

1/y-2 = v

 =  \frac{1}{y - 2}  =  \frac{5}{1}

 = 5(y - 2) = 1 \\  \\  = 5y - 10 = 1 \\  \\  = 5y = 1 + 10 \\  \\  = 5y = 11 \\  \\  = y =  \frac{11}{5}

\bf\underline{\underline{\green{HENCE:-}}}

  • x= 8/7
  • y= 11/5

__________________________________________

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