Question

Solve for x and y: 2^x-1 *7^2y-3 = 196​

Answer 1

Answer:

x = 3 & y = 5/2

Step-by-step explanation:

Since, 2^x-1 * 7^2y-3 = 196

Therefore, 2^x-1 * 7^2y-3 = 14^2

So, 2^x-1 * 7^2y-3 = 2^2 * 7^2

Here, we have 2 and 7 as common bases for the exponents x-1 & 2 and 2y-3 & 2, respectively.

And since, bases are same ; so, exponents are also same.

=> x - 1 = 2 & 2y - 3 = 2

=> x = 2 + 1 & y = (2 + 3) ÷ 2

=> x = 3 & y = 5/2

Hope it helps u !!!!!!