Question

solve for x and y 2√x+y=6, 3x + √y=8

Answer 1

Answer:

Given, equation: $$3x - 2y = 6$$.

Now, to check whether (1,2) will lie on the line 3x−2y=6, we have to put the value of (x,y) in the given equation.

LHS =3(1)−2(2)=3−4=−1



=6 or RHS

Therefore, the point (1,2) will not lie on the line 3x−2y=6.

Now, at x=4, we have,

3(4)−2y=6

y=3

Again, 3x−2y=6

⇒ At x=0,y=−3 and at y=0,x=2