Question

solve for X and Y; 2x + 3 Y= 9 ; 4 x + 6 Y = 15

Answer 1

Answer:

Given 2x + 3y = 9 <- equation 1

Also given 4x+6y =15 <- equation 2

Now we test for the conditions of solvability to check if the above question has a unique solution or not.

So now, a1 = 2, b1 = 3 and c1=9

Again, a2=4, b2 = 6 and c2=15

Hence, a1/a2 = 2/3

b1/b2= 4/6 or 2/3

But for a unique solution the condition is a1/a2 is not equal to b1/b2.

Therefore, above pair of equations don't have a uniques solution