Question

Solve for x and y
2x -3y =10
X - 4y = 9

Answer 1

Answer:

in the first equation we multiply with 1

and

in the second equation we multiply with 2

2x-3y=10. 1 equation

2x-8y=18 2 equation

+5y= -8

so y= -8/5.

so we apply the value of y{-8/5} in second equation

x-4{-8/5}=9

x+32/5=9

x=9/1-32/5

x=45-32/5

x=13/5.

so y= -8/5

and. x=13/5

Answer 2

$\large{\underline{\underline{\mathfrak{\green{\sf{Answer:-}}}}}}$.

• $\:x\:=\frac{-8}{5}$

• $\:y\:=\frac{13}{5}$

$\large{\underline{\underline{\mathfrak{\sf{Given\:Here:-}}}}}$.

• $\:2x \:-\: 3y\:=\:10$..........(1)

• $\:x\:- \:4y\:=\:9$ ...........(2)

[ Multiply by 2 in (2) , ]

We can write , these equations ,

• $\:2x \:- \:3y \:=\:10$

• $\: 2x \:- \:8 y\: =\:18$

Subtract this ,

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$\implies\:5y\:=\:-8$

$\implies\:y\:=\frac{-8}{5}$

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[ Keep value of y in equation (2) ]

$\implies\:x\:-\:4\:×\frac{-8}{5}\:=\:9$

$\implies\:x\:=\:9\:-\frac{32}{5}$

$\implies\:x\:=\frac{45-32}{5}$

$\implies\boxed{\:x\:=\frac{13}{5}}$

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$\large{\underline{\underline{\mathfrak{\green{\sf{Answer\:checkup :-}}}}}}$.

Given Equation

• x - 4y = 9

Keep value of x and y ,

$\implies\frac{13}{5}\:-\:4×\frac{-8}{5}\:=\:9$

$\implies\frac{13+32}{5}\:=\:9$

$\implies\frac{45}{5}\:=\:9$

$\boxed{\implies\:9\:=\:9}$

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