Solve for X and y: 2x+6y=24 22x+3y=48
Answers
Answer:
2x + 6y = 24 ........eq(1)
22x + 3y = 48 ........eq(2)
eq(2) ×2 = 22x×2 + 3y×2 = 48×2 =
= 44x + 6y = 96.......eq(3)
eq(3)-eq(1) = 44x-2x + 6y-6y = 96-24
= 40x + 0 = 72
x = 72/40 = 9/5 = 1.8
substitute x=1.8 on eq(1)
⇒ 2×1.8 + 6y = 24
3.6 + 6y = 24
6y = 24 - 3.6 = 20.4
y = 20.4/6 = 3.4
x=1.8
y=3.4
hope this helps
multiply 22x+3y=48 by 2 ,we get: 44x+6y=96......eq.1
now subtracting 2x+6y=24 from 44x+6y=96, we get:
44x+6y=96
2x+6y=24
-. -. -
42x+ 0y=72
42x=72
x=72/42
x= 12/7
putting value of x in 2x+6y=24
= 2*12/7+6y=24
= 24/7 +6y =24
= 6y =24 - 24/7
= 6y =. (24*7 - 24)/7
= y = ( 168 - 24 ) 7*6
= y = 144 / 42
=. y = 24 / 7
value of x=12/7 and y=24/7