Solve for x and y: 2x2+y2 = 8+5xy and y-x = 2.
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Step-by-step explanation:
SOLUTION 13 : Begin with x2 + xy + y2 = 1 . Differentiate both sides of the equation, getting
D ( x2 + xy + y2 ) = D ( 1 ) ,
2x + ( xy' + (1)y ) + 2 y y' = 0 ,
so that (Now solve for y' .)
xy' + 2 y y' = - 2x - y ,
(Factor out y' .)
y' [ x + 2y ] = - 2 x - y ,
and the first derivative as a function of x and y is
(Equation 1)
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