solve for x and y: 3^(x-y) = 27 ; 3^(x+y) = 243
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x=4 y=1
3^x-y =3^x÷3^y=27
3^x+y=3^x×3^y=243
let 3^x=a and 3^y=b
nowa÷b=27 a/b=27 a=27b ________(1)
anda×b=243 putting the value of (1)
27b×b=243 b^2=243/27
b^2=9 b=3
and a=27b=81
3^x=a=81 3^4
3^y=b=3 3^1
hope it helps you thanks
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