solve for x and y (√32)x power ÷2y+1 power , 16 4-x /2 power -8 y power =0
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Answer:
2x=−1+
3
i⇒x=
2
−1+
3
i
=ω, cube root of unity
∴(1−x
2
+x)
6
−(1−x+x
2
)
6
=(1−ω
2
+ω)
6
−(1−ω+ω
2
)
6
=(−2ω
2
)
6
−(−ω−ω)
6
, since 1+ω+ω
2
=0
=2
6
ω
12
−2
6
ω
6
=2
6
−2
6
=0, since ω
3
=1
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