solve for x and y
3a/x - 2b/y + 5 = 0
a/x + 3b/y - 2 = 0
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Answered by
123
3a/x - 2b/y + 5 = 0 ---------------(1)
a/x + 3b/y - 2 = 0 ------------(2)
multiply with 3 in equation (2)
3a/x + 9b/y - 6 = 0 ----------------(3)
subtract equation (3) from (1)
11b/y = 11
y = b
put y = b in equation (1)
3a/x - 2 + 5 = 0
x = -a
so
x = -a and y = b
a/x + 3b/y - 2 = 0 ------------(2)
multiply with 3 in equation (2)
3a/x + 9b/y - 6 = 0 ----------------(3)
subtract equation (3) from (1)
11b/y = 11
y = b
put y = b in equation (1)
3a/x - 2 + 5 = 0
x = -a
so
x = -a and y = b
ritikabansi27:
Thank You so much
Answered by
39
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