Solve for x and y: 3x+4y=13 and 2x-3y=3
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x = 3and y = 1 these are values of x and y
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3x+4y=13----1eqs.
2x-3y=3------2eqs.
multi.1eqs.by2
And multi.2eqs.by3
by applying eliminating method,
6x+8y=26
6x-9y=9
- + -
--------------
17y=17
y=1
and, similarly
putting y=1 in eqs1.
we get,
x=3
Therefore x=3and y=1
2x-3y=3------2eqs.
multi.1eqs.by2
And multi.2eqs.by3
by applying eliminating method,
6x+8y=26
6x-9y=9
- + -
--------------
17y=17
y=1
and, similarly
putting y=1 in eqs1.
we get,
x=3
Therefore x=3and y=1
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