Question

solve for x and y ,3x+5y=15,12x+20y=60 using elimination method​

Answer 1

Given :

3x+5y=15,

12x+20y=60

use elimination method​

To Find : solve for x and y

Solution:

3x+5y=15       Eq1

12x+20y=60  Eq2

4 * Eq1 - Eq2

=> 4(3x + 5y) - (12x + 20y)  = 4(15) - 60

=> 12x + 20y - (12x + 20y) = 60 - 60

=> 0 = 0

Which is always true independent of x and y

Hence x, y ∈ R

Infinite solution exists.

As  3x+5y=15 and 12x+20y=60  represent same line.

Learn More:

solve X + Y = 83 and 4 x + Y = 182 by elimination method, Letv ...

brainly.in/question/17301814

solve the following by elimination method: x+y/3 = 0.9 ; 11 / ( x + y/2 ...

brainly.in/question/10926830