Math, asked by masterishan2007, 1 month ago

solve for x and y :

4/x + 3y = 14
3/x - 4y = 23

Answers

Answered by iamalexi
1

Answer:

y= -2

x=1/5

Step-by-step explanation:

so first

let 4/x+3y=14-------(1)

3/x-4y=23‐--------(2)

Equation (1)×3 : x12+9y=42

Equation (2)×4 : x12−16y=92

Subtract two equations ;

⇒25y=−50

⇒y=−2

Substituting 'y' in equation (1),we get ;

⇒x=51

Answered by tejas130405
0

Answer:

x= 1/5 y = -2

Step-by-step explanation:

 \frac{4}{x}  + 3y = 14

 \frac{4}{x}  = 14 - 3y

3y = 14 -  \frac{4}{x}

3y =  \frac{14x - 4}{x}

y =  \frac{14 x - 4}{3x}

  \frac{3}{x}  - 4y = 23

Putting Y value

 \frac{3}{x}  - 4 (\frac{14x - 4}{3x} ) = 23

 \frac{3}{x}  -  \frac{56x - 16}{3x}  = 23

 \frac{9 - 56x + 16}{3x}  = 23

 25 - 56x = 69x

69x +56x = 25

125x = 25

x =  \frac{1}{5}

Putting X value in eq. 1

 \frac{4}{ \frac{1}{5} }  + 3y = 14

20 + 3y = 14

3y =  - 6

y =  - 2

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