solve for x and y 4/x+3y=14, 3/x-4y =23 by elimination method
Answers
Answered by
8
Answer:
y = -2
x = 1/5
Step-by-step explanation:
Taking 1 / x as a
Eq 1
4a + 3y = 14
Eq 2
3a - 4y = 23
Multiplying Eq 1 by 3 and Eq 2 by 4.
We get
Eq 1
12a + 9y = 42
Eq 2
12a - 16y = 92
Subtracting Eq 1 from Eq 2
12a-16y-(12a+9y) = 92 - 42
12a-16y-12a-9y = 50
-25y = 50
y = -2
Putting y in Eq 1
4a+3y=14
4a+3(-2)=14
4a-6=14
4a=20
a=5
x=1/a = 1/5
Therefore
y=-2
x=1/5
Answered by
6
let 1/x=a
4a+3y=14------(1) multiply by 4
3a-4y=23---------(2)multiply by 3
then we get
16a+12y=56
9a - 12y =69
--------------------
25a=125
a=125/25
a=5----(3)
put the value of a in equation (1)
4a+3y=14
4×5+3y=14
3y=14-20
3y=-6
y=-2
now
1/x=a
1/x=5
x=1/5
and
y=-2
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