Math, asked by anmol2923, 1 year ago

solve for x and y 4/x+3y=14, 3/x-4y =23 by elimination method

Answers

Answered by niveditachetan
8

Answer:

y = -2

x = 1/5

Step-by-step explanation:

Taking 1 / x as a

Eq 1

4a + 3y = 14

Eq 2

3a - 4y = 23

Multiplying Eq 1 by 3 and Eq 2 by 4.

We get

Eq 1

12a + 9y = 42

Eq 2

12a - 16y = 92

Subtracting Eq 1 from Eq 2

12a-16y-(12a+9y) = 92 - 42

12a-16y-12a-9y = 50

-25y = 50

y = -2

Putting y in Eq 1

4a+3y=14

4a+3(-2)=14

4a-6=14

4a=20

a=5

x=1/a = 1/5

Therefore

y=-2

x=1/5

Answered by arjun7774
6

let 1/x=a

4a+3y=14------(1) multiply by 4

3a-4y=23---------(2)multiply by 3

then we get

16a+12y=56

9a - 12y =69

--------------------

25a=125

a=125/25

a=5----(3)

put the value of a in equation (1)

4a+3y=14

4×5+3y=14

3y=14-20

3y=-6

y=-2

now

1/x=a

1/x=5

x=1/5

and

y=-2

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