Solve for x and y : 41x+53y=135, 53x+51y=147
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Answer: I think your q is incorrect as second eq should have 41y not 51y.
41x + 53y = 135 ------> (I)
53x + 41y = 147 ---------> (II)
adding (I) and (II), we get
94x + 94y = 282
94(x+y) = 282
x+y = 3 ------> (III)
Substracting eq (I) from eq (II),
12x - 12y = 12
12 (x-y) = 12
x-y = 1 ---------> (IV)
solving eq (III) and eq (IV) by elimination method,
x + y = 3
+x - y = 1
-----------
2x = 4
x = 2
from eq (III),
x + y =3
2 + y= 3
y = 1
hence the values of x and y are 2 and 1 respectively.
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