Question

Solve for x and y 47x+3ly = 63 31 x +47 y = 15​

Answer 1

Answer:

${◆Answer}$

Step-by-step explanation:

47x+31y=63(eqn 1)

47x+31y=63(eqn 1)31x+47y=15(eqn 2)

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we get

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we get

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)using elimination method for eqn 3and eqn4

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)using elimination method for eqn 3and eqn4 x+y=1

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)using elimination method for eqn 3and eqn4 x+y=1 x-y=3

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)using elimination method for eqn 3and eqn4 x+y=1 x-y=32x=4

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)using elimination method for eqn 3and eqn4 x+y=1 x-y=32x=4x=2

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)using elimination method for eqn 3and eqn4 x+y=1 x-y=32x=4x=2putting value of x in x+y=1,by solving we get

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)using elimination method for eqn 3and eqn4 x+y=1 x-y=32x=4x=2putting value of x in x+y=1,by solving we gety=-(negative)1

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)using elimination method for eqn 3and eqn4 x+y=1 x-y=32x=4x=2putting value of x in x+y=1,by solving we gety=-(negative)1therefore

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)using elimination method for eqn 3and eqn4 x+y=1 x-y=32x=4x=2putting value of x in x+y=1,by solving we gety=-(negative)1thereforex=2

47x+31y=63(eqn 1)31x+47y=15(eqn 2)adding both eqn,we get78x+78y=78 dividing this eqn by 78,we getx+y=1 (be it eqn 3)subtracting eqn 1 and eqn 2,we get16x-16y=48dividing this eqn by 16, we getx-y=3(be it eqn 4)using elimination method for eqn 3and eqn4 x+y=1 x-y=32x=4x=2putting value of x in x+y=1,by solving we gety=-(negative)1thereforex=2y=-1