Question

Solve for x and y
4x + 6/y=15
6x-8/y=14
Hence find the 'p' if y=px-2

Answer 1

4x + 6/y=15...(i)

6x-8/y=14......(ii)

Multiply equation (i) by 'y' on both sides,

4xy + 6 = 15y

4xy - 15y = -6.....(iii)

Multiply equation (ii) by 'y' on both sides,

6xy - 8 = 14y

6xy - 14y = 8.......(iv)
 
Multiplying equation (iii) by 3 and (iv) by 2,

    12xy - 45y = -18
    12xy -28y = 16
-    (-)     (+)      (-)
-------------------------
             -17 y = - 34

Thus y = 2

Substituting y = 2 in equation (i),
 
     4x + 6/2 = 15

     4x = 12

Thus x = 3

Guven that y = px - 2

Substitute the values of x and y

2 = p (3) - 2
3 p = 4

p = 4/3

Answer 2

Answer:

Step-by-step explanation:

4x+6/y=15.....(1)

6x-8/y=14...(2)

Multiply eq 1 by 'a' on both sides

4xa+6=15a

4xa-15a=-6...(3)

Multiply eq 2 by 'a' on both sides

6xa-8=14b

6xa-14q=8....(4)

Multiply eqs 3 by 3 & 4 by 2

12xa-45a=-18

12xa-28a=16

_. +. _

-17a=-34

a=-34/-17

a=2

Sub a=2 in eq1

4x×6/2=15

4x=12

x=3

Given that y=px-2

Substitute the values x&u

2=p(3)-2

3p=4

P=4/3