solve for x and y 4x-y=0, 3x+2y=14
Answers
Step-by-step explanation:
Given equations are
4x−y−4=0...(1)
3x+2y−14=0...(2)
Write y in terms of x for equation (1).
4x−y−4=0
⇒y=(4x−4)
Substitute different values of x in the above equation to get corresponding values of y
For x=1,y=0
For x=0,y=−4
For x=2,y=4
Now plot the points A(1,0), B(0,−4) and C(2,4) in the graph paper and join A, B and C to get the graph of 4x−y−4=0
Similarly, Write y in terms of x for equation (2).
3x+2y−14=0
⇒y=
2
(14−3x)
Substitute different values of x in the above equation to get corresponding values of y
For x=0,y=7
For x=2,y=4
For x=4,y=1
Now plot the points D(0,7), E(2,4) and F(4,1) in the graph paper and join D, E and F to get the graph of 3x+2y−14=0
From the graph:
Both the lines intersect each other at point C(2,4) and y-axis at B(0,−4) and D(0,7) respectively
∴ Area of △BCD=
2
1
(base×altitude)
=
2
1
×11×32 sq.units
=11 sq.units.
Answer:
1. (4x-y=0)×3
=12x-y=0 -----------(1)
2. (3x+2y=14)×4
=12x+8y=56 ------------(2)
By using elimination method
12x-y=0
- 12x-8y=56
+ -
————————
7y=-56
————————
7y=-56
y=-56/7
y=-8
By putting y=-8 on eq1
12x-y=0
12x-(-8)=0
12x+8=0
12x=-8
x=-8/12
x=-2/3