Question

Solve for X and Y:5/y+6y=13;3/x+4y=7,x=0​

Answer 1

Your question needs a correction. The correct question is :

Solve for x and y in the equations : $\tt{\frac{5}{x} + 6y = 13}$ and $\tt{\frac{3}{x} + 4y = 7}$

$\mathfrak{\huge{Answer:}}$

Let $\frac{1}{x}$ = m

The equations change into :

5m + 6y = 13 and 3m + 4y = 7

Solve for the value of m :-

m = $\sf{\frac{13 - 6y}{5}}$

Find the other value of m from the other equation :-

m = $\sf{\frac{7 - 4y}{3}}$

Keep these values equal to each other as :

m = m

=》 $\tt{\frac{13 - 6y}{5} = \frac{7 - 4y}{3}}$

=》 3 ( 13 - 6y ) = 5 ( 7 - 4y )

=》 39 - 18y = 35 - 20y

=》 39 - 35 = 18y - 20y

=》 4 = (-2y)

=》 y = (-2)

m = $\sf{\frac{13 - 6y}{5}}$

=》 m = $\sf{\frac{13 + 12}{5}}$

=》 m = $\sf{\frac{25}{5}}$

=》 m = $\sf{5}$

You have found the value of m, and now, you can keep this value equal to the variable we kept earlier

m = $\frac{1}{x}$ = 5

=》 x = $\sf{\frac{1}{5}}$

Thus, the final answer is :

$\boxed{\tt{y = (-2)\:and\:x = \frac{1}{5}}}$