solve for x and y 6(ax+by)=3a+2b 6(bx-ay)=3b-2a
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Sol.
The given equation are:
6(ax+by)=3a+2b
6(bx-ay)=3b-2a
Equation (1) and (2) can be re -written as.
multiple (1a) by a and (2a) by b and adding them , we have
subtracting x = 1/2 in (1a) , we get
Hence, the solution of the given system of equations is x= 1/2 and y = 1/3
Hope it's helps you .
here, is Ur answer ...
Sol.
The given equation are:
6(ax+by)=3a+2b
6(bx-ay)=3b-2a
Equation (1) and (2) can be re -written as.
multiple (1a) by a and (2a) by b and adding them , we have
subtracting x = 1/2 in (1a) , we get
Hence, the solution of the given system of equations is x= 1/2 and y = 1/3
Hope it's helps you .
Answered by
0
The given equation are:
6(ax+by)=3a+2b
6(bx-ay)=3b-2a
Equation (1) and (2) can be re -written as.
multiple (1a) by a and (2a) by b and adding them , we have
subtracting x = 1/2 in (1a) , we get
Hence, the solution of the given system of equations is x= 1/2 and y = 1/3
Hope it's helps you .
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