Question

solve for x and y 6 upon x minus y - 3 1 by minus 2 is equal to 1, 5 upon x minus 1 + 1 upon y minus 2 is equal to 2 where x is not equal to 1 and bi is not equal to 2​

Answer 1

$\textbf{Given:}$

$\textsf{Equations are}$

$\mathsf{\dfrac{6}{x-1}-\dfrac{3}{y-2}=1}$

$\mathsf{\dfrac{5}{x-1}+\dfrac{1}{y-2}=2}$

$\textbf{To find:}$

$\textsf{Solution of the given equations}$

$\textbf{Solution:}$

$\mathsf{\dfrac{6}{x-1}-\dfrac{3}{y-2}=1}$......(1)

$\mathsf{\dfrac{5}{x-1}+\dfrac{1}{y-2}=2}$.......(2)

$\mathsf{(1)+3{\times}(2)\implies}$

$\mathsf{\dfrac{6}{x-1}-\dfrac{3}{y-2}=1}$

$\mathsf{\dfrac{15}{x-1}+\dfrac{3}{y-2}=6}$

$\mathsf{\dfrac{21}{x-1}=7}$

$\mathsf{\dfrac{3}{x-1}=1}$

$\mathsf{3=x-1}$

$\implies\mathsf{x=3+1}$

$\implies\boxed{\mathsf{x=4}}$

$\mathsf{put\;x=4\;in\;(1)\;we\;get}$

$\mathsf{\dfrac{6}{3}-\dfrac{3}{y-2}=1}$

$\mathsf{2-\dfrac{3}{y-2}=1}$

$\mathsf{2-1=\dfrac{3}{y-2}}$

$\mathsf{1=\dfrac{3}{y-2}}$

$\mathsf{3=y-2}$

$\mathsf{y=3+2}$

$\implies\boxed{\mathsf{y=5}}$

$\textbf{Answer:}$

$\textsf{Solution is x=4 and y=5}$

$\textbf{Find more:}$

Solve the following pair of equations by reducing them to a pair of linear equation.

5/x+y +1/x-y =2 and

10/x+y+3/x-y =5​

https://brainly.in/question/15071188