Math, asked by 1KingArjun, 10 months ago

Solve for x and y : 6/x + y = 7/x - y + 3 , 1/2(x + y) = 1/3(x - y) where x + y ≠ 0 and x – y ≠ 0.
Plzz solve!!
If it is right then only I will mark Brainliest!!

Answers

Answered by sristusudharani
2

Step-by-step explanation:

Let 1/x + y = a , 1/x - y = b

6a = 7b + 3 ---- (i)

 

a / 2 = b / 3 a = 2b / 3

Putting value of a in (i) 

 6*2b/3 = 7b + 3  

4b = 7b + 3

-3b = 3

 b = -1

 

a = -2/ 3 

x + y = - 3 / 2 ------- (iii)

x - y = - 1 ----- (iv)

(iii) + (iv)

x + y + x - y = -3/2 - 1

2x = -5/2 x = - 5 /4

 

y = - 1 /4 

Ans: x = - 5 / 4, y = - 1 / 4 

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