Question

solve for x and y:
6/x+y = 7/x-y+3; 1/2(x+y)=1/3(x-y) where x+y is not equal to zero and x-y is not equal to zero

Answer 1

Answer:

6/x+y=7/x-y+3

6(x-y+3)=7(x+y)

6x-6y+18=7x+7y

7x-6x+7y+6y=18

x+13y=18(Keep it as 1st equation)

Now take other given terms

1/2x+2y=1/3x-3y

3x-3y=2x+2y

3x-2x=2y+3y

x=5y

x-5y=0(Keep it as 2nd equation)

Now subtract this equations for eliminating 'I'm

1st-2nd

that is

x+13y-(x-5y)=18-(0)(since LHS SHOULD BE SUBTRACTED BY LHS AND RHS SHOULD BE BY RHS)

x+13y-x+5y=18

13y+5y=18

18y=18

y=18/18

y=1

sub y value in equation 1 or 2

I'll in equation 2

x-5y=0

x-5(1)=0

x-5=0

x=5

Therefore the value of x=5 and y=1

Where x+y and x-y is not equal to 0

Answer 2

Answer:

yes

your answer is correct

please mark as brainlist