Question

Solve for x and y:
6x+3y=7xy
3x+9y=11xy

Answer 1

hope it's helpful.....

Answer 2

Hey there!
Down here ⏬

$6x + 3y = 7xy$

$= > \: \: ( \frac{6}{y} ) + ( \frac{3}{x} ) = 7 \: \: \: \: \: \: (1)$

$3x + 9y = 11xy$

$= > \: ( \frac{3}{y} ) + ( \frac{9}{x} ) = 11 \: \: \: \: \: \:(2)$

Multiply eq (1) by 2 and
Substract eq (1), we get,

$( \frac{6}{y} ) + ( \frac{3}{x} ) = 7$

$( \frac{6}{y} ) + ( \frac{18}{x} ) = 22$

$- 15x = - 15$

$x = 1$

Putting value of x=1 in eq. (1) we get,

$( \frac{6}{y} ) + 3 = 7$

$\frac{6}{y} = 4$

$y = \frac{6}{4} = \frac{3}{2}$

Hope helped :D