Question

solve for x and y √7x+√11y=77 and √3x-√5y=15​

Answer 1

Step-by-step explanation:

√7x + √11y = 77 _________ (1)

√3x - √5y = 15 _________ (2)

Multiplying eqⁿ (1) by √3 and (2) by √7 resp.

√21x + √33y = 231

√21x + √35y = 105

- - -

——————————

(√33 - √35)y = 126

y = 126 / (√33 - √35 )

put in (1)

√7x + √11 × 126 / (√33- √35) = 77

√7x = 77 - 126√11 / (√33-√35)

x = [77( √33 - √ 35 ) - 126√ 11] / √7

Answer 2

Step-by-step explanation:

i) Here a₁/a₂ = √7/√3 and b₁/b₂ = -√11/√5

i) Here a₁/a₂ = √7/√3 and b₁/b₂ = -√11/√5==> The ratio of coefficients are not equal.

i) Here a₁/a₂ = √7/√3 and b₁/b₂ = -√11/√5==> The ratio of coefficients are not equal.ii) Hence by the theory of system linear equations, they have unique solution. But here both the equations are equal to zero. So the system has trivial solution.

i) Here a₁/a₂ = √7/√3 and b₁/b₂ = -√11/√5==> The ratio of coefficients are not equal.ii) Hence by the theory of system linear equations, they have unique solution. But here both the equations are equal to zero. So the system has trivial solution.That is (x, y) = (0, 0)

i) Here a₁/a₂ = √7/√3 and b₁/b₂ = -√11/√5==> The ratio of coefficients are not equal.ii) Hence by the theory of system linear equations, they have unique solution. But here both the equations are equal to zero. So the system has trivial solution.That is (x, y) = (0, 0)iii) Also if you were to apply the substitution method and solving,

from the 2nd, x = (√5/√3)y.

from the 2nd, x = (√5/√3)y.Substituting this value of x in 1st, (√5/√3 + √11)y = 0; ==> y = 0; so x = 0

bts army forever

...........b....