Question

solve for x and y, 9^x=(3^y)^-2, 81^y=3^2×(27) ^x
pls answer fast​

Answer 1

Step-by-step explanation:

first

9^x = (3^y)^-2

(3^2)^x = (3^y)^-2

since base is same

2x = -2y

2x + 2y = 0----------1☆

second

81^y = 3^2 × (27)^x

3^4y = 3^2 × 3^3x

since base is same

4y = 2 + 3x

4y - 3x = 2-----------2☆

Now, 1☆ × 3 = 6x + 6y = 0--------3

2☆ × 2 = 8y - 6x = 4--------4

Now, value of x is equal in 3 and 4

so, 3+4 = 14y = 4

y = 2/7--------5

Now, putting the the value of 5 in 2☆

4×2/7 - 3x = 4

8/7 - 3x = 4

3x = 4 - 8/7

3x = 20/7

x = 20/21

Hence the value of x = 20/21

y = 2/7

I hope it will help you

Answer 2

hope friends this will help you, thank you good night