Question

solve for x and y. ax+by=3ab a²x+ b²y=a+b.​

Answer 1

Answer:

$ax + by = 3ab...(i)$

${a}^{2} x + {b}^{2} = a + b...(ii)$

$substitute \: the \: value \: of \: x \: in(ii).we \: get$

${a}^{2} + {b}^{2} \frac{a(3b - x)}{b} = a + b$

${a}^{2} x + {b}^{2} \frac{a(3b - x)}{b} = a + b$

${a}^{2}x + 3a {b}^{2} - abx = a + b$

$x ( {a}^{2} - ab) = a + b - 3a {b}^{2}$

$x = \frac{a + b - 3a {b}^{2} }{ {a}^{2} - ab}$

$therefore \: y = \frac{a(3b - x)}{b}$

$= \frac{a(3b - \frac{a + b - 3a {b}^{2} }{ {a}^{2 - ab} } }{b(a - b)}$

$= \frac{3 {a}^{2} b - a - b}{b(a - b)}$

Step-by-step explanation:

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