Solve for x and y ax+by=a^2-b^2 and bx+ay=0
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adding two eqns...
ax+bx+by+ay = a^2 - b^2
x(a+b) + y(a+b) = (a+b) (a-b)
(x+y)(a+b) = (a+b) (a-b)
x+y = a-b
ax+bx+by+ay = a^2 - b^2
x(a+b) + y(a+b) = (a+b) (a-b)
(x+y)(a+b) = (a+b) (a-b)
x+y = a-b
X=a and y= -b
okay
bhai wo last step me mene galat equation me X ki value rakh di hn
Tik hai ko
Answered by
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ax + by = a2 - b2.......(1)
bx + ay = 0..................(2)
_____________
(a-b)x + (b-a)y = a2 - b2 (subtracting 2 from 1)
or,
(a-b)x - (a-b)y = (a+b)(a-b)
or, (a-b)(x-y) = (a+b)(a-b)
or, (x-y) = a + b
or, x = a + b + y...............(3)
b(a+b+y) + ay = 0 (putting the value of x from 3)
or, ab + b2 + by + ay = 0
or, y(a+b) = -b2 - ab
or, y(a+b) = -b(a+b)
or, y = -b
bx - ab = 0
or, bx = ab
or, x = a
Hence, x = a, y = -b
____
mark it Brainliest if it helps you.
bx + ay = 0..................(2)
_____________
(a-b)x + (b-a)y = a2 - b2 (subtracting 2 from 1)
or,
(a-b)x - (a-b)y = (a+b)(a-b)
or, (a-b)(x-y) = (a+b)(a-b)
or, (x-y) = a + b
or, x = a + b + y...............(3)
b(a+b+y) + ay = 0 (putting the value of x from 3)
or, ab + b2 + by + ay = 0
or, y(a+b) = -b2 - ab
or, y(a+b) = -b(a+b)
or, y = -b
bx - ab = 0
or, bx = ab
or, x = a
Hence, x = a, y = -b
____
mark it Brainliest if it helps you.
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