Math, asked by Sahu07, 1 year ago

Solve for x and y -
ax + by = a+b/2
3x + 5y = 4


raushansinghrajput: here x= 10a-3b/10a-6b and y=2a-3b/10a-6b

Answers

Answered by assalterente
3

Answer:

Hence, the solutions are y = \frac{5a - 3b}{10a + 6b}. and x = \frac{4-5(\frac{5a-3b}{10a + 6b} )}{3}.

Step-by-step explanation:

Our question is: Solve for x and y - ax + by = a+b/2 and 3x + 5y = 4.

First, lets pick the second equation and organize it in terms of x, hence we get x = \frac{4 - 5y}{3}.

Thus, we can substitute this x in the first equation, and we would get a(\frac{4 - 5y}{3}) + by = \frac{a+b}{2}.

Hence, we need to solve this equations in terms of y, hence we will achieve y equal to \frac{5a - 3b}{10a + 6b}.

Hence, the solutions are y = \frac{5a - 3b}{10a + 6b}. and x = \frac{4-5(\frac{5a-3b}{10a + 6b} )}{3}.

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