Math, asked by psingh54, 6 hours ago

solve for x and y: ax + by = b - a and bx - ay= - (a + b)

Answers

Answered by mathdude500
1

Answer:

\boxed{\sf \:  \: x =  - 1 \:  \: and \:  \: y = 1  \: }\\

Step-by-step explanation:

Given pair of linear equation is

\sf \: ax + by = b - a -  -  - (1) \\

and

\sf \: bx - ay =  - (a + b) -  -  - (2) \\

On multiply equation (1) by a and (2) by b, we get

\sf \:  {a}^{2} x + aby = ab -  {a}^{2}  -  -  - (3) \\

and

\sf \:  {b}^{2} x - aby =  - ab -  {b}^{2}  -  -  - (4) \\

On adding equation (3) and (4), we get

\sf \:  {a}^{2}x +  {b}^{2}y =  -  {a}^{2} -  {b}^{2} \\

\sf \:  x({a}^{2}+  {b}^{2}) =  -({a}^{2}  +  {b}^{2}) \\

\implies\sf \: x =  - 1 \\

On substituting x = - 1 in equation (1), we get

\sf \: a( - 1) + by = b - a \\

\sf \:  - a + by = b - a \\

\sf \:   by = b\\

\implies\sf \: y = 1 \\

Hence,

\implies\sf \: x =  - 1 \:  \: and \:  \: y = 1 \\

\rule{190pt}{2pt}

Concept Used :-

There are 4 methods to solve this type of pair of linear equations.

1. Method of Substitution

2. Method of Eliminations

3. Method of Cross Multiplication

4. Graphical Method

I prefer here Method of Eliminations :-

To solve systems using elimination, follow this procedure:

The Elimination Method

Step 1: Multiply each equation by a suitable number so that the two equations have the same leading coefficient.

Step 2: Subtract the second equation from the first to eliminate one variable and get new equation in one variable.

Step 3: Solve the new equation to get a value of variable.

Step 4: Substitute the value of variable thus evaluated into either Equation 1 or Equation 2 and get the value of other variable.

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