Math, asked by suhanisaroha50, 10 months ago

solve for x and y by changi them into linear equation 2(3x-y)=5xy and 2(x+3y)
=5xy

Answers

Answered by suchitrabanik56
2

Answer:

x = 0 or, x = 4/5

Step-by-step explanation:

2(3x-y) = 2(x+3y)

2(3x-y) = 2(x+3y)or, 4x= 4y

2(3x-y) = 2(x+3y)or, 4x= 4yor, x = y

2(3x-y) = 2(x+3y)or, 4x= 4yor, x = y 2(3x-x) = 5x^2

2(3x-y) = 2(x+3y)or, 4x= 4yor, x = y 2(3x-x) = 5x^2or, x(5x-4) = 0

so, x = 0 or, x = 4/5


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Answered by sam7544
3

2(3x-y)=5xy

=> 6x - 2y = 5xy _______(1)

2(x+3y)= 5xy

=> 2x + 6y = 5xy

(2)×3 => 6x +18y = 5xy

-(1)×1 => 6x - 2y = 5xy

_______-___+____-_______

(1) - (2) => 20y = 0

=>. y = 0

(1) => 6x - 2y = 5xy

=> 6x- 2×0 = 5x × 0

=> 6x = 0

=> x = 0

there fore,

x = 0 and y = 0

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