Math, asked by shifataj, 1 year ago

solve for X and Y by elimination method 2x+3y=7 and 4x+3y=11

Answers

Answered by SameerPagar
17
firstly write both equations
2x+3y=7 ...(1)
4x+3y=11 ....(2)
subtracting equation 1 from 2
4x+3y=11
-
2x+3y=7
As per elimination method eliminate the variable having same coefficient
In the above example eliminate 3y
therefore we get eq. as
2x= 4
x = 4/2
x =. 2
Now put this value in any one of the both eq.
Putting x=2 in 1
2 × 2 +3y = 7
4+ 3y =7
3y=7 -4
3y =3
y= 3/3
y= 1
write final solution
(x ,y) = (2 ,1)
Answered by KaurSukhvir
0

Answer:

For the given equations, the value of x is equal to 2 and the value of y is equal to 1.

Step-by-step explanation:

We have given the two equations:

2x + 3y = 7                                                                          ............(1)

4x + 3y = 11                                                                          .............(2)

According to the elimination method eliminate the variable having same coefficient.

On subtracting equation (1) from equation (2);

(4x + 3y) - (2x + 3y) = 11 - 7

4x + 3y - 2x -3y = 4

2x = 4

x = 2

Now substitute the value of 'x' which is x=2 in the equation (1).

2(2) + 3y = 7

4 + 3y = 7

3y = 7 - 4

3y = 3

y = 1

Therefore, the value of x is equal to 2 and value of y is equal to 1.

The solution of given equations (x, y) is equal to (2, 1).

Similar questions