Math, asked by vdev254, 7 months ago

solve for x and y by elimination method 2x-5y+4=0 and 2x+y-8=0​

Answers

Answered by koushikj401
7

2x-5y+4=0

2x+y-8=0

(-) (-) (+)

sub -6y+12=0

-6y= -12

y= -12/-6

y= 2

2x+y-8=0

2x+2-8=0

2x-6=0

2x=6

X=6/2

X=3

Answered by ishwarsinghdhaliwal
5

2x-5y+4=0 => 2x-5y =-4 ...... (1)

2x+y-8=0 =>2x+y =8 ..... (2)

Subtract equation (2) from equation (1), we get

-6y=-12

y=-12/-6

y=2

Substitute the value of y in equation (1), we get

2x-5(2)=-4

2x-10=-4

2x=-4+10

2x=6

x=6/2

x=3

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