Question

solve for x and y by the method of elimination 2x–y=5, 3x–5y=4​

Answer 1

Answer:

$x=\frac{20}{7}\ \ \ \ \text{and} \ \ \ \ y= \frac{5}{7}$

Step-by-step explanation:

We are given the equations

• $2x-y=5$                       .......Equation (1)
• $3x-5y=4$                      ....... Equation (2)

To Find :

Values of x and y by the method of elimination.

Solution :

Substituting the value of y from equation (1) to equation (2) to eliminate 'x'.

value of y from Equation(1)

                                $y=2x-5$                   .........Equation(3)

From Equation(2)

                          $3x-5(2x-5)=5$

                           $3x-10x+25=5$

                          $7x=20$

                          $x=\frac{20}{7}$

Substituting the value of x in the Equation(3) we get

                        $y=2(\frac{20}{7})-5$

                       $y=\frac{40}{7}-5$

                       $y=\frac{40-35}{7}$

                      $y=\frac{5}{7}$

Hence we get $x=\frac{20}{7}\ \ \ \ \text{and} \ \ \ \ y= \frac{5}{7}$

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Answer 2

Answer:

3 and 1 are the required value of a and y.

Step-by-step explanation:

Explanation:

Given that, 2x - y = 5 and 3x - 5y = 4

Elimination method - The elimination approach involves taking one variable out of the system of linear equations by utilising addition or subtraction together with multiplication or division of the variable coefficients.

So, according to the question we solve these equation by using elimination method.

Step 1:

From the question we have, 2x - y = 5 and 3x - 5y = 4

By elimination method,

3(2x - y = 5)     ...............(i)

2(3x - 5y = 4)   ...........(ii)

-       +        -  

         7y =  7

⇒ y = $\frac{7}{7}$ = 1

Now, on putting y = 1 in equation(i) we get,

⇒  2x - y = 5

⇒ 2x - 1 = 5

⇒ 2x = 5 + 1 = 6

⇒ x = $\frac{6}{2}$ = 3

So, x = 3 and y = 1

Final answer:

Hence, 3 and 1 are the required value of a and y.

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