solve for x and y by the method of elimination x minus y + 1 equal to zero and X + 2 Y - 12 is equal to zero
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x - y + 1 = 0 (eqn. no. 1)
x + 2y - 12 = 0 (eqn. no. 2)
eliminate x by subtracting eqn. no. 2 from eqn. no. 1
x - y + 1 = 0 - (x + 2y - 12 = 0)
x - y + 1 - x - 2y + 12 = 0
- 3y + 13 = 0
- 3y = - 13
y = (-13)/(-3)
y = 13/3
putting the value of y in the eqn. no. 1
x - y + 1 = 0
x - 13/3 + 1 = 0
3x - 13 + 3 = 0
3x - 10 = 0
3x = 10
x = 10/3
Hence, the value of y = 13/3 & x = 10/3
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