Question

Solve for x and y for the following pair of equation
px+qy=p-q , qx-py=p+q.

⚠️No copied Answer ​

Answer 1

Answer:

x 3 and p is 8 hope it helps

Answer 2

Answer:

Ans)......

x and y can be found by using the following formula:

x = (p-q)/(p^2+q^2) and y = (p+q)/(p^2+q^2).

Step-by-step explanation:

**In this case, the elimination method is used to find x and y.

First, we multiply the first equation by q and the second equation by p:

pqx + q^2y = pq - q^2.............................1

p^2x - pqy = p^2 + pq...............................2

Adding the two equations gives:

(p^2 + q^2)x = p^2 + 2pq

Therefore, x = (p^2 + 2pq) / (p^2 + q^2)

Substituting x back into the equation (1):

p(p^2 + 2pq) / (p^2 + q^2) + qy = p - q

Solving for y, we get:

y = (p - q - p(p^2 + 2pq) / (p^2 + q^2)) / q = (p + q) / (p^2 + q^2)

Finally, we have:

x = (p^2 + 2pq) / (p^2 + q^2) and y = (p + q) / (p^2 + q^2)

.......HOPE IT HELPS YOU.........